... 5hrs chem + 1.5hrs of add maths => 3hrs of headache + 2hrs sleepless sleep
therefore tmr's
2hrs S.S + 3hrs Geog + 1.5hrs of Chem => Xhrs headaches + Yhrs of sleepless sleep...
note: 1a= 2h
Find X and Y
[X and Y are positive]
common factor: chem [c]
-> 5c +1.5a = 3h + 2s [equ:1]
-> 2 SS + 3g +1.5c = Xh + Ys [equ:2]
equ2 x 10= 20 SS + 30g + 15c = 10X h + 10Y s [ equ:3]
equ1 x 3 = 15c+ 4.5a = 9h + 6s [ equ:4]
equ4 - equ3 => 15c+ 4.5a - 20 SS - 30g -15c = (9-10X)h + (6-10Y)s
= 4.5 a -20 SS - 30g = (9-10X)h + (6-10Y)s [ equ:5]
equ 5 x 2=> 9a -40ss -60g = (18-20X)h + (12-20Y)s
sub a=2h =>-40ss - 60g = (36-20X)h + (12-20Y)s [equ:6]
equ6/4 => -10ss- 15g = (9-5X)h + (3-5Y)s
10ss + 15g = (-9+5X)h + (-3+5Y)s
5(2ss + 3g) = (-9+5X)h + (-3+5Y)s
(2ss + 3g) = ((-9+5X)h + (-3+5Y)s)/5
(2ss + 3g) = (-1.8+X)h + ( -0.6 + Y)s
therefore as X not= 0: X > 1.8
therefore as Y not= 0: Y > 0.6
therefore c= 0.4s
therefore 2hrs of SS and 3hrs of Geog gives headaches of more than 1.8hrs and more than 0.6 hrs of sleepless sleep...
ok i am crazy... thanks to chem and add math... if u have an answer to the above question please send it to me... thanks
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